document.write( "Question 1036914: The swim portion of a triathlon follows a triangular path. The swimmers start by swimming to a buoy that is placed 900m from the starting point at an angle of N15° E. Upon reaching the buoy, the swimmers change their heading to E30° S and swim another 1200m. Finally they return to the starting point and jump on their Bikes. How long was the swim in total?\r
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Algebra.Com's Answer #651610 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
We have a triangle with angles A, B, and C, and sides a, b, c.
\n" ); document.write( "One side is 900m. Find the other 2 sides
\n" ); document.write( "The angles of every triangle add up to 180 degrees
\n" ); document.write( "A+B+C = 180º
\n" ); document.write( "15+30 = 45
\n" ); document.write( "180-45 = 135 degrees is your third angle. Let's call them:
\n" ); document.write( "A = 15
\n" ); document.write( "B = 30
\n" ); document.write( "C = 135
\n" ); document.write( "And the sides, we'll call side b = 900m.
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\n" ); document.write( "The sine rule says:
\n" ); document.write( "a/sinA = b/sinB = c/sin C
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\n" ); document.write( "Let's first find side c:
\n" ); document.write( "c/sinC = b/sinB Multiply both sides times sinC:
\n" ); document.write( "c = bsinC/sinB
\n" ); document.write( "= 900sin135/sin30 Use your calculator and you get:
\n" ); document.write( "= 1272.79 is side c
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\n" ); document.write( "Let's find side a:
\n" ); document.write( "a/sinA = b/sinB
\n" ); document.write( "a = bsinA/sinB
\n" ); document.write( "900sin15/sin30
\n" ); document.write( "= 465.87 is your third side
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\n" ); document.write( "How long was the swim?
\n" ); document.write( "900+1272.79+465.87 = 2638.66 meters.
\n" ); document.write( "See the picture I made you below
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