document.write( "Question 1036851: A rectangular area is to be fenced in using two types of fencing. The front and back uses fencing costing RM 5 a foot while sides use fencing costing RM 4 a foot. If the area of the rectangle must contain 500 square feet, what should the dimensions of the rectangle be in order to keep the cost at a minimum ? \n" ); document.write( "
Algebra.Com's Answer #651602 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular area is to be fenced in using two types of fencing.
\n" ); document.write( " The front and back uses fencing costing RM 5 a foot while sides use fencing costing RM 4 a foot.
\n" ); document.write( " If the area of the rectangle must contain 500 square feet, what should the dimensions of the rectangle be in order to keep the cost at a minimum ?
\n" ); document.write( ":
\n" ); document.write( "let L = the length of the area
\n" ); document.write( "let w = the width
\n" ); document.write( "Area
\n" ); document.write( "L * w = 500
\n" ); document.write( "L = \"500%2Fw\"
\n" ); document.write( ":
\n" ); document.write( "Cost of fencing
\n" ); document.write( "Cost = 5(2L) + 4(2W)
\n" ); document.write( "C = 10L + 8w
\n" ); document.write( "Replace L with 500/w
\n" ); document.write( "C = 10(\"500%2Fw\" + 8w
\n" ); document.write( "graph this equation :y = \"5000%2Fw\" + 8w
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+60%2C+-100%2C+600%2C+%285000%2Fx%29%2B8x%29+\"
\n" ); document.write( "Cost is on the y axis, width on the x axis
\n" ); document.write( "w = 25 ft for min cost
\n" ); document.write( "then
\n" ); document.write( "L = 500/25; minimum cost would calculate to: $400
\n" ); document.write( "L = 20 ft is length
\n" ); document.write( "
\n" ); document.write( "
\n" );