document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036891>Question 1036891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the surface area of a cone with radius 6 inches and a slant height of 9 inches.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651588 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+pi*r(r+ sqrt(h^2+r^2)); h^2+r^2=L^2, where L is the slant height.  Therefore, A+pi*r(r+L)<BR>\n" );
document.write( "A=pi*6(6+sqrt(81))=6*pi(15)=90 pi in^2. </SPAN>\n" );
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