document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036833>Question 1036833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that X is inversely proportional to the square of Y. It is known that x = 8 for a particular value of Y. When Y is increased bu 200%, find<BR>\n" );
document.write( "(a) the value of X,<BR>\n" );
document.write( "(b) the percentage change in the value of X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651559 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2=k/x.  When x=8<BR>\n" );
document.write( "y^2=k/8; k=8y^2<BR>\n" );
document.write( "increasing y 200% is tripling <BR>\n" );
document.write( "(3y)^2=9y^2, so y^2 is increased 9 fold<BR>\n" );
document.write( "k=8y^2<BR>\n" );
document.write( "9y^2=8y^2/x<BR>\n" );
document.write( "x=8/9<BR>\n" );
document.write( "The per cent change is the decrease over the original amount or 64/9 divided by 9 or 64/81 or 79%. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );