document.write( "Question 1036845: how many 2 digit numbers are possible such that the sum of their digits is equal to twice the difference between digits? \n" ); document.write( "
Algebra.Com's Answer #651550 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The sum can't be odd, because then it wouldn't be divisible by 2. \n" ); document.write( "Therefore, only even digits or odd digits are allowed. \n" ); document.write( "11,13,15,17,19--13 works and 31 \n" ); document.write( "20,22,24,26,28----26 works and 62 \n" ); document.write( "31,33,35,37,39----39 works and 93 \n" ); document.write( "40,42,44,46,48--no \n" ); document.write( "51,53,55,57,59--no \n" ); document.write( "yx \n" ); document.write( "y+x=2(y-x) \n" ); document.write( "y+x=2y-2x \n" ); document.write( "3x=y \n" ); document.write( "======== \n" ); document.write( "y+x=2(x-y) \n" ); document.write( "y+x=2x-2y \n" ); document.write( "x=3y \n" ); document.write( "6 numbers are possible \n" ); document.write( " \n" ); document.write( " |