document.write( "Question 1036683: The denominator of a fraction is four less than twice the numerator if three is added to both the numerator and denominator, the new fraction is equal to two-thirds. What is the original fraction? \n" ); document.write( "
Algebra.Com's Answer #651506 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let n = the numerator of the original fraction \n" ); document.write( "let d = the denominator \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "The denominator of a fraction is four less than twice the numerator \n" ); document.write( "d = 2n - 4 \n" ); document.write( ": \n" ); document.write( "if three is added to both the numerator and denominator, the new fraction is equal to two-thirds. \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "3(n+3) = 2(d+3) \n" ); document.write( "3n + 9 = 2d + 6 \n" ); document.write( "3n = 2d + 6 - 9 \n" ); document.write( "3n = 2d - 3 \n" ); document.write( "replace d = (2n-4) \n" ); document.write( "3n = 2(2n-4) - 3 \n" ); document.write( "3n = 4n - 8 - 3 \n" ); document.write( "3n - 4n = -11 \n" ); document.write( "-n = -11 \n" ); document.write( "n = 11 \n" ); document.write( "Find d using the 1st equation d = 2n - 4 \n" ); document.write( "d = 2(11) - 4 \n" ); document.write( "d = 18 \n" ); document.write( ": \n" ); document.write( " What is the original fraction? \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check this for yourself, in the statement \n" ); document.write( "\"if three is added to both the numerator and denominator, the new fraction is equal to two-thirds. \" \n" ); document.write( " \n" ); document.write( " |