document.write( "Question 1036775: A candy distributor needs to mix a 10% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 18% fat-content chocolate. How many kilograms of each kind of chocolate must they use? \n" ); document.write( "
Algebra.Com's Answer #651474 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount of 10% chocolate needed. Then: \n" ); document.write( ".10n+.50(100-n)=.18(100) \n" ); document.write( ".10n-.50n+50=18 \n" ); document.write( ".4n=32 \n" ); document.write( "n=32/.4=80 kilograms of 10% needed, 20 kilograms of 50% chocolate needed!!!!!!!!!! \n" ); document.write( " |