document.write( "Question 1036745: Working together, Jo and Ralph can do the garden chores in 6 hours. It takes Jo twice as long as Ralph to do the work alone. How many hours does it take Jo working alone?\r
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Algebra.Com's Answer #651436 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Working together, Jo and Ralph can do the garden chores in 6 hours. It takes Jo twice as long as Ralph to do the work alone.
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document.write( "Let J be Jo's rate of work.\r\n" );
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document.write( "Then Ralph's rate of work is twice of it, and is equal to 2J.\r\n" );
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document.write( "When they work together, their combined rate of work is the sum of individual rates, i.e. J + 2J = 3J.\r\n" );
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document.write( "We are given that 3J = \"1%2F6\".\r\n" );
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document.write( "Hence, J = \"1%2F18\".\r\n" );
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document.write( "It means that it takes 18 hours for Jo to complete the job working alone.\r\n" );
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\n" ); document.write( "\n" ); document.write( "You can find many other solved joint-work problems in the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Using Fractions to solve word problems on joint work,\r
\n" ); document.write( "\n" ); document.write( "    - Solving more complicated word problems on joint work,\r
\n" ); document.write( "\n" ); document.write( "    - Selected joint-work word problems from the archive \r
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\n" ); document.write( "\n" ); document.write( "Read them, and you will learn how to solve such problems once and for all. \r
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\n" ); document.write( "\n" ); document.write( "Read them and get trained in solving joint-work problems.\r
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