document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036669>Question 1036669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the zeros of y=3x^2+2x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651384 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF we replace x with zero we get y = 0+0+1 =1. The point (0,1) is called they Y intercept. \r<BR>\n" );
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document.write( "IF we set y = 0, we get the second part of the equation that is supposed to be equal to zero. That is a quadratic equation and there is not any real number solution to this quadratic equation as the number under radical would be a negative number. This means that there is not any x intercept. <BR>\n" );
document.write( "In terms of graph, it means that curve doesn't touch the x axis. In other words Y can't be zero. </SPAN>\n" );
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