document.write( "Question 1036650: My teacher asked me this question
\n" ); document.write( "3x + 5y = 4
\n" ); document.write( "2x + 4y = 6\r
\n" ); document.write( "\n" ); document.write( "She said I could use either substitution or elimination. I want to show both, can you help me solve this equation using both substitution and elimination (separately) ?
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Algebra.Com's Answer #651374 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
3x + 5y = 4
\n" ); document.write( "2x + 4y = 6
\n" ); document.write( "=========
\n" ); document.write( "6x+10y=8
\n" ); document.write( "-6x-12y=-18
\n" ); document.write( "-2y=-10
\n" ); document.write( "y=5
\n" ); document.write( "2x+20=6
\n" ); document.write( "2x=-14
\n" ); document.write( "x=-7
\n" ); document.write( "(-7.5)
\n" ); document.write( "Check with substitution
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\n" ); document.write( "2x+4y=6
\n" ); document.write( "2x=-4y+6
\n" ); document.write( "x=-2y+3
\n" ); document.write( "substitute into first equation
\n" ); document.write( "3(-2y+3)+5y=4
\n" ); document.write( "-6y+9+5y=4
\n" ); document.write( "-y=-5
\n" ); document.write( "y=5
\n" ); document.write( "x will be -7.
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