document.write( "Question 1036650: My teacher asked me this question
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document.write( "3x + 5y = 4
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document.write( "2x + 4y = 6\r
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document.write( "She said I could use either substitution or elimination. I want to show both, can you help me solve this equation using both substitution and elimination (separately) ? \n" );
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Algebra.Com's Answer #651374 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 3x + 5y = 4 \n" ); document.write( "2x + 4y = 6 \n" ); document.write( "========= \n" ); document.write( "6x+10y=8 \n" ); document.write( "-6x-12y=-18 \n" ); document.write( "-2y=-10 \n" ); document.write( "y=5 \n" ); document.write( "2x+20=6 \n" ); document.write( "2x=-14 \n" ); document.write( "x=-7 \n" ); document.write( "(-7.5) \n" ); document.write( "Check with substitution \n" ); document.write( "==================== \n" ); document.write( "2x+4y=6 \n" ); document.write( "2x=-4y+6 \n" ); document.write( "x=-2y+3 \n" ); document.write( "substitute into first equation \n" ); document.write( "3(-2y+3)+5y=4 \n" ); document.write( "-6y+9+5y=4 \n" ); document.write( "-y=-5 \n" ); document.write( "y=5 \n" ); document.write( "x will be -7. \n" ); document.write( " \n" ); document.write( " |