document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89680>Question 89680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Point A (4,1)is in the standard (x,y) coordinate plane. What must be the coordinates of point B so that the line x=2 is the perpendicular bisector of AB?<BR>\n" );
document.write( "   A.(-6,1)  B.(4-,-1)  C.(-4,3)  D.(-2,1)  E.(8,1)\r<BR>\n" );
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document.write( "Note:Please explain step by step for each problem.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65134 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=2 is a vertical line ... to be perpendicular, the line AB must be horizontal so B has the same y-coordinate as A\r<BR>\n" );
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document.write( "if x=2 bisects AB then 2 is midway between the x-coordinates of A and B ... (4+x)/2=2 ... 4+x=4 ... x=0\r<BR>\n" );
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document.write( "B is (0,1) ... none of the above </SPAN>\n" );
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