document.write( "Question 1036554: A contractor agrees to lay a road 3000 m long in 30 days. 50 men are employed and they work for 8 hours say. After 20 working days, he finds that only 1200 m of the road is completed. How many more men does he need to employ in order to finish the project on time if each man now works 10 hours a day? \n" ); document.write( "
Algebra.Com's Answer #651301 by ankor@dixie-net.com(22740)\"\" \"About 
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A contractor agrees to lay a road 3000 m long in 30 days.
\n" ); document.write( " 50 men are employed and they work for 8 hours say. After 20 working days, he finds that only 1200 m of the road is completed.
\n" ); document.write( ":
\n" ); document.write( "Find the number of man-hrs required to complete 1200 meters
\n" ); document.write( "50*8*20 = 8000 man-hrs
\n" ); document.write( "Find the no. of meters per man-hr
\n" ); document.write( "\"1200%2F8000\" = .15 meters per per man-hr
\n" ); document.write( ":
\n" ); document.write( " How many more men does he need to employ in order to finish the project on time if each man now works 10 hours a day?
\n" ); document.write( "Find how many man-hr required to do the remaining 1800 meters
\n" ); document.write( "\"1800%2F.15\" = 12000 man-hrs
\n" ); document.write( "let m = no. of additional men required to accomplish this in 10 days working 10 hrs a day
\n" ); document.write( "10*10*(m+50) = 12000
\n" ); document.write( "100m + 5000 = 12000
\n" ); document.write( "100m = 12000 - 5000
\n" ); document.write( "100m = 7000
\n" ); document.write( "m = 7000/100
\n" ); document.write( "m = 70 more men
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