document.write( "Question 1036563: Sammy and Sally each carry a bag containing a banana, a chocolate bar, and a licorice stick. Simultaneously, they take out a single food item and consume it. The possible pairs of food items that Sally and Sammy consumed are as follows.\r
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document.write( "chocolate bar - chocolate bar\r
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document.write( "licorice stick - chocolate bar\r
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document.write( "banana - banana\r
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document.write( "chocolate bar - licorice stick\r
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document.write( "licorice stick - licorice stick\r
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document.write( "chocolate bar – banana\r
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document.write( "banana - licorice stick\r
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document.write( "licorice stick - banana\r
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document.write( "banana - chocolate bar\r
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document.write( "Find the probability that no chocolate bar was eaten.\r
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document.write( " A. 4/9
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document.write( " B. 5/9
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document.write( " C. 7/9
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document.write( " D. 5/8 \n" );
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Algebra.Com's Answer #651260 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It's 4/9. \n" ); document.write( "You can count the 5 chocolate bar containing possibilities above \n" ); document.write( "or \n" ); document.write( "they are independent probabilities, and the probability of each one not picking a chocolate bar is 2/3. Multiply (2/3) by (2/3)=(4/9) \n" ); document.write( " |