document.write( "Question 1036568: If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%? \n" ); document.write( "
Algebra.Com's Answer #651250 by Boreal(15235)\"\" \"About 
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x invested at 8%
\n" ); document.write( "80000-x (the rest) invested at 10%
\n" ); document.write( ".08x+.10(80000-x)=7800
\n" ); document.write( ".08x+8000-.10x=7800
\n" ); document.write( "-.02x=-200
\n" ); document.write( "x=$10,000 which at 8% is $800
\n" ); document.write( "70,000 (ANSWER) of @10% is $7000.
\n" ); document.write( "they add to $7800.
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