document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036511>Question 1036511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi , im really not sure about how to go about and solve this question, i tried it and i got 3C3 * 3! *6! where 3C3 is the 3 blanks filling in with 3 boys , 6! ways to seat the girls and 3! due to order importance, could you please help me with the question \r<BR>\n" );
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document.write( "1)  In how many ways can 6 girls and 3 boys sit on a row of 9 chairs in such a way that no two boys sit next to each other? \r<BR>\n" );
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document.write( "Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651220 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 6! ways of seating the 6 girls.  Then there are 7 spaces in which you can insert the boys (including both ends), and this can be done in 7P3 ways.  Therefore by the fundamental principle of multiplication, there are 6!*7P3 = 151,200 ways in which no two boys sit next to each other. </SPAN>\n" );
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