document.write( "Question 1036531: How to solve 3x+2y=14 and y=X+2
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Algebra.Com's Answer #651205 by addingup(3677)\"\" \"About 
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3x+2y=14 and y=X+2
\n" ); document.write( "So you want to solve this system of equations, correct?
\n" ); document.write( "3x+2y=14
\n" ); document.write( "and
\n" ); document.write( "y=X+2 subtract 2 on both sides and y on both sides (and flip the equation):
\n" ); document.write( "x-y = -2 Multiply both sides times 2
\n" ); document.write( "2x-2y = -4
\n" ); document.write( "Now add this equation to the first:
\n" ); document.write( "3x+2y = 14
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\n" ); document.write( "2x-2y = -4
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\n" ); document.write( "5x = 10
\n" ); document.write( "Divide both sides by 5:
\n" ); document.write( "x = 2
\n" ); document.write( "Take one of the equations and find y, I'll use the 2nd equation in your problem:
\n" ); document.write( "y = x+2
\n" ); document.write( "y = 2+2 = 4
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\n" ); document.write( "Proof:
\n" ); document.write( "3x+2y = 14
\n" ); document.write( "3(2)+2(4) = 14
\n" ); document.write( "6+8 = 14 Correct
\n" ); document.write( "Next:
\n" ); document.write( "y = x+2
\n" ); document.write( "4 = 2+2 Correct
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