document.write( "Question 1036483: How to determine the equation of a parabola with vertex (7,-2) and passing the point (6,0)? Graph the parabola.
\n" ); document.write( "So far I have gotten
\n" ); document.write( "y=a(x+b)^2+c
\n" ); document.write( "y=a(x+6)^2+0
\n" ); document.write( "

Algebra.Com's Answer #651174 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "How to determine the equation of a parabola with vertex (7,-2) and passing the point (6,0)? Graph the parabola.
\n" ); document.write( "So far I have gotten
\n" ); document.write( "y=a(x+b)^2+c
\n" ); document.write( "y=a(x+6)^2+0
\n" ); document.write( "
No, no, no!! The vertex form of a parabola is the equation: \"y+=+a%28x+-+h%29%5E2+%2B+k\". In this case, (h, k) = (7, 2), and (x, y) = (6, 0). 
\n" ); document.write( "You substituted (x, y) for (h, k). That's incorrect! Try again! \n" ); document.write( "
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