document.write( "Question 89596: rizen is 5 years older than JB. Find their present ages if the product of Rizen's age 4 years from now and JB's age 5 years ago is 51 \n" ); document.write( "
Algebra.Com's Answer #65117 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
rizen is 5 years older than JB. Find their present ages if the product of Rizen's age 4 years from now and JB's age 5 years ago is 51
\n" ); document.write( "--------------
\n" ); document.write( "NOW DATA:
\n" ); document.write( "JB is \"x\" yrs old ; Rizen is \"x+5\" yrs old:
\n" ); document.write( "-------------
\n" ); document.write( "4 yrs from NOW and 5 years from NOW DATA:
\n" ); document.write( "Jb will be \"x+4\" yrs old; Rizen will be \"x+10\" yrs old
\n" ); document.write( "-------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "(x+4)(x+10) = 51
\n" ); document.write( "x^2+14x+40 = 51
\n" ); document.write( "x^2+14x-11 = 0
\n" ); document.write( "x=[-14+-sqrt(14^2-4*1*-11)]/2
\n" ); document.write( "x=[-14 +- sqrt(240)]/2
\n" ); document.write( "Positive answer:
\n" ); document.write( "x = 0.75 (JB's age NOW)
\n" ); document.write( "x+5 = 5.75 (Rizen's age NOW)
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );