document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89589>Question 89589</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The price and the quantity x sold of a certain product  obey the demand question.<BR>\n" );
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document.write( " x=-5p+100, 0 is less than or equal to p and p is <BR>\n" );
document.write( " less than or equal to 20\r<BR>\n" );
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document.write( "a) express the Revenue R as a function of x.\r<BR>\n" );
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document.write( "b) What is the revenue if 15 units are sold?\r<BR>\n" );
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document.write( "17) A wire 10 meters long is to be cut into two pieces. One piece will be shaped as a square and other piece will be shaped as a circle:<BR>\n" );
document.write( "a) express the total area A enclosed by the pieces of wire as a function of the length x of a side of the square.<BR>\n" );
document.write( "b) What is the domain of A?\r<BR>\n" );
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document.write( "Thank you sooo much!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65116 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The price and the quantity x sold of a certain product obey the demand question.\r<BR>\n" );
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document.write( "x=-5p+100, 0<=p<=20 <BR>\n" );
document.write( "Solve for P which is price:<BR>\n" );
document.write( "p=(100-x)/5<BR>\n" );
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document.write( "a) express the Revenue R as a function of x.<BR>\n" );
document.write( "Revenue = (price)*(quantity)<BR>\n" );
document.write( "Revenue =  [(100-x)/5]*x = (x/5)(100-x) = 20x-(1/5)(x^2)<BR>\n" );
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document.write( "b) What is the revenue if 15 units are sold? <BR>\n" );
document.write( "R(15) = 20*15 - (1/5)(15^2)<BR>\n" );
document.write( "R(15) = 300 - 45 = $255<BR>\n" );
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document.write( "17) A wire 10 meters long is to be cut into two pieces. One piece will be shaped as a square and other piece will be shaped as a circle:<BR>\n" );
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document.write( "Let one of the pieces have length x; the other piece will have length 10-x<BR>\n" );
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document.write( "a) express the total area A enclosed by the pieces of wire as a function of the length x of a side of the square.<BR>\n" );
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document.write( "Circle area using the (10-x) piece of wire:<BR>\n" );
document.write( "Perimeter = 10-x = 2(pi)r<BR>\n" );
document.write( "r = (10-x)/2pi = <BR>\n" );
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document.write( "Area of circle = (pi)r^2 <BR>\n" );
document.write( "Area of circle = (pi)[(10-x)/2pi]^2 = (10-x)^2/4(pi)<BR>\n" );
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document.write( "Area of the square using the \"x\" piece of wire:<BR>\n" );
document.write( "One side = (1/4)x<BR>\n" );
document.write( "Area of square = side^2 = [x^2/16]<BR>\n" );
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document.write( "Total Area = area of square + area of circle.<BR>\n" );
document.write( "A = (x^2/16) + [(10-x)^2/4(pi)]<BR>\n" );
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document.write( "b) What is the domain of A? <BR>\n" );
document.write( "Domain: 0<=x<=10<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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