document.write( "Question 1036402: In a random sample of 800 refreshment-dispensing machines, it is found that an average of 8.1 ounces is dispensed with a standard deviation of 0.85 ounce.\r
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document.write( "Find the probability that the true mean is between 8.157 and 8.185. Round your answer to the tenths place. \n" );
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Algebra.Com's Answer #651159 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z(a)=(8.157-8.1)*sqrt(800)/0.85. Using z-value with sample size of 800. Dividing the denominator by the sample size is the same as multiplying it in the numerator. \n" ); document.write( "z=1.89 \n" ); document.write( "z(b)=(8.185-8.1)*sqrt(800)/0.85 \n" ); document.write( "z=2.83 \n" ); document.write( "The probability is 2.7% (the distance between those two z-values. \n" ); document.write( " \n" ); document.write( " |