document.write( "Question 1036402: In a random sample of 800 refreshment-dispensing machines, it is found that an average of 8.1 ounces is dispensed with a standard deviation of 0.85 ounce.\r
\n" ); document.write( "\n" ); document.write( "Find the probability that the true mean is between 8.157 and 8.185. Round your answer to the tenths place.
\n" ); document.write( "

Algebra.Com's Answer #651159 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
z(a)=(8.157-8.1)*sqrt(800)/0.85. Using z-value with sample size of 800. Dividing the denominator by the sample size is the same as multiplying it in the numerator.
\n" ); document.write( "z=1.89
\n" ); document.write( "z(b)=(8.185-8.1)*sqrt(800)/0.85
\n" ); document.write( "z=2.83
\n" ); document.write( "The probability is 2.7% (the distance between those two z-values.
\n" ); document.write( "
\n" ); document.write( "
\n" );