document.write( "Question 1036404: In a random sample of 5,000 exams, the average score was 500 points with a standard deviation of 90 points.\r
\n" ); document.write( "\n" ); document.write( "Find the probability that the true mean is between 495 and 500.
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Algebra.Com's Answer #651157 by Boreal(15235)\"\" \"About 
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The z-score is = (value-mean)/s/sqrt (n). I'm assuming normality here and don't need a t-test with n=5000.
\n" ); document.write( "=(495-500)/90/sqrt(5000)
\n" ); document.write( "=-5(sqrt(5000)/90
\n" ); document.write( "That is a z between -3.92 and 0 or 49.9955%
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