document.write( "Question 1036462: Compute\r
\n" ); document.write( "\n" ); document.write( "1 - 2 + 3 - 4 + ... + 2005 - 2006\r
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Algebra.Com's Answer #651136 by Aldorozos(172)\"\" \"About 
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1-2=-1
\n" ); document.write( "3-4=-1
\n" ); document.write( "5-6=-1
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\n" ); document.write( "2005-20056=-1\r
\n" ); document.write( "\n" ); document.write( "Here we have (2006/2)*(-1)= -1003
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