document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036444>Question 1036444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam has already biked  1	4  of all the distance and 12 miles, and he still needs to bike  3	8  of the total distance and 9 miles. What’s the total distance? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651114 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Most likely you meant 1/4 of the distance and 3/8 of the distance\r<BR>\n" );
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document.write( "1/4 of d + 12<BR>\n" );
document.write( "3/8 of d + 9\r<BR>\n" );
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document.write( "we add 1/4 and 3/8 of the distance and we get 5/8 of the distance. If he biked 5/8 of the distance and also biked 12 additional and 9 additional miles to cover the rest of the distance this means that the rest of the distance which is 8/8 - 5/8 = 3/8 is equivalent to 9+12 = 21\r<BR>\n" );
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document.write( "3/8 * d = 21. d=21*8 divided by 3 = 7*8 = 56  </SPAN>\n" );
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