document.write( "Question 1036386: A bag contains 30 coins, all of which are either quarters or dimes. If the total value of the coins is $5.85, how many of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #651038 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Q=number of quarters; D=number of dimes \n" ); document.write( ". \n" ); document.write( "Q+D=30 \n" ); document.write( "D=30-Q . Use this to substitute for D below \n" ); document.write( ". \n" ); document.write( "$0.10D+$0.25Q=$5.85 . Substitute for D from above. \n" ); document.write( "$0.10(30-Q)+$0.25Q=$5.85 \n" ); document.write( "$3.00-$0.10Q+$0.25Q=$5.85 \n" ); document.write( "$0.15Q=$2.85 \n" ); document.write( "Q=19 \n" ); document.write( ". \n" ); document.write( "ANSWER 1: There were 19 quarters. \n" ); document.write( ". \n" ); document.write( "D=30-Q=30-19=11 \n" ); document.write( ". \n" ); document.write( "ANSWER 2: There were 11 dimes. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "$0.10D+$0.25Q=$5.85 \n" ); document.write( "$0.10(11)+$0.25(19)=$5.85 \n" ); document.write( "$1.10+$4.75=$5.85 \n" ); document.write( "$5.85=$5.85 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |