document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036382>Question 1036382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Length of a rectangle is 4 less than 3 times the width. if the perimeter is 40, find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651035 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 3W-4<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2L+2W = 40 Substitute for L:<BR>\n" );
document.write( "2(3W-4)+2W = 40<BR>\n" );
document.write( "6W-8+2W = 40<BR>\n" );
document.write( "8W = 48<BR>\n" );
document.write( "W = 6 This is the width, and the Length:<BR>\n" );
document.write( "L = 3(6)-4 = 14<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2(6)+2(14)= 40<BR>\n" );
document.write( "12+28 = 40 Correct. </SPAN>\n" );
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