document.write( "Question 1036358: The square of one more than number x is 13 more than itself. Find the value of x where x is positive.
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Algebra.Com's Answer #651034 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( " $\"%28x%2B1%29%5E2=x%2B13\"$
\n" ); document.write( " $\"x%5E2%2B2x%2B1=x%2B13\"$
\n" ); document.write( " $\"x%5E2%2Bx-12=0\"$
\n" ); document.write( " $\"%28x%2B4%29%28x-3%29=0\"$
\n" ); document.write( " $\"x%2B4=0\"$ $\"OR\"$ $\"x-3=0\"$
\n" ); document.write( " $\"x=-4\"$ $\"OR\"$ $\"x=3\"$
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\n" ); document.write( "Since x=-4 is not positive, then answer is x=3.
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\n" ); document.write( "CHECK:
\n" ); document.write( "For x=3:
\n" ); document.write( " $\"%28x%2B1%29%5E2=x%2B13\"$
\n" ); document.write( " $\"%283%2B1%29%5E2=3%2B13\"$
\n" ); document.write( " $\"4%5E2=16\"$
\n" ); document.write( " $\"16=16\"$
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