document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036359>Question 1036359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the measure of an angle is twenty less than the measure of its compliment what is the measure of the angle i know that complementary angles add up to 90 degrees so should I subtract 20 from 90 degrees to get 70 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #651033 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=651033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Let A=measure of the angle<BR>\n" );
document.write( "Let B=measure of complement=A+20<BR>\n" );
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document.write( "A+B=90 degrees Substitute (A+20) for B<BR>\n" );
document.write( "A+(A+20)=90<BR>\n" );
document.write( "2A+20=90<BR>\n" );
document.write( "2A=70<BR>\n" );
document.write( "A=35 The measure of the original angle is 35 degrees.<BR>\n" );
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document.write( "B=A+20=35+20=55 The measure of the complement is 55 degrees.<BR>\n" );
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document.write( "Let B= complement<BR>\n" );
document.write( "Let A=original angle=B-20<BR>\n" );
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document.write( "A+B=90 degrees<BR>\n" );
document.write( "(B-20)+B=90 degrees<BR>\n" );
document.write( "2B=110 degrees<BR>\n" );
document.write( "B=55 degrees The complement is 55 degrees<BR>\n" );
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document.write( "A=B-20=55-20=35 The original angle was 35 degrees.<BR>\n" );
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document.write( "(NOTE: COMPLEMENT rather than COMPLIMENT refers to relationship of angles)<BR>\n" );
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document.write( "Since you did not ask a particular question, there is no way to give a particular answer. You can subtract 20 degrees if you know what to do from there, or add 20 degrees if you know how to compute from there. The method given above may give you some understanding of the math that is happening. </SPAN>\n" );
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