document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036290>Question 1036290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A set of data has a normal distribution with a mean of 110 and a standard deviation of 20.\r<BR>\n" );
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document.write( "Find the interval about the mean within which 90% of the data lie.\r<BR>\n" );
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document.write( "-93.5-126.5<BR>\n" );
document.write( "-77-143<BR>\n" );
document.write( "-78-142<BR>\n" );
document.write( "-103.5-136.5\r<BR>\n" );
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document.write( "Find the probability that a value selected at random from this data is between 100 and 120.\r<BR>\n" );
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document.write( "-38.8%<BR>\n" );
document.write( "-50%<BR>\n" );
document.write( "-95.5%<BR>\n" );
document.write( "-68.3%\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650963 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a normal distribution z.95=1.645<BR>\n" );
document.write( "110+/-1.645*20=110+/-32.9, or (77.1, 142.9).  It is the second choice.<BR>\n" );
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document.write( "Here, it is 1/2 of a sd on each side, and that is the probability of -0.5<z<0.5, and that is 38.8% </SPAN>\n" );
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