document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036258>Question 1036258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve this -  If a , b are the zeroes to f the polynomial p(x)=x^2-p(x+1)-c such that (a+1)(b+1)=0. What is the value of c </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650903 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a,b be the zeroes of p(x).\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%28x%29+=+x%5E2-p%28x%2B1%29-c++=+x%5E2+-+px+-+p+-+c ALIGN=MIDDLE  ALT=\"p%28x%29+=+x%5E2-p%28x%2B1%29-c++=+x%5E2+-+px+-+p+-+c\"   DISABLED_style= \"max-width:90%; height:auto;\" > ==> -p = -(a+b) ==> p = a+b, \r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "-p - c = ab.\r<BR>\n" );
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document.write( "Now (a+1)(b+1)= ab + a+b+1 =0 ==> -p-c + p + 1 = 0\r<BR>\n" );
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document.write( "==> c = 1, after simplifying.\r<BR>\n" );
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