document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89545>Question 89545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each of the following systems by using either addition or substitution. If a unique solution does not exist, state whether the system is dependent or inconsistent.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "10x + 2y = 7 <BR>\n" );
document.write( " y= -5x + 3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65090 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying the second equation by -2 gives -2y=10x-6 ... adding this result to the first equation gives\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "10x+2y+(-2y)=7+(10x-6) ... 10x=10x+1 ... this is an inconsistent result </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );