document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036238>Question 1036238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In geometry, if the sum of the angles is 180O, the two are called supplementary angles. Find the measurement of two supplementary angles is their difference is 54O.	\r<BR>\n" );
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document.write( "The denominator of a fraction is one more than the numerator. If the numerator is decreased by 1 and the denominator is increased by 2, the resulting fraction is ½. Find the original fraction.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650895 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I will solve these based on my best guess.<BR>\n" );
document.write( "X+y= 180<BR>\n" );
document.write( "X- y = 540<BR>\n" );
document.write( "We can subtract 360 from 540 and we get 180<BR>\n" );
document.write( "We can rewrite<BR>\n" );
document.write( "X+y= 180<BR>\n" );
document.write( "X-y = 180<BR>\n" );
document.write( "Now we can add the two equations<BR>\n" );
document.write( "2x = 380 therefore x = 180 if x = 180 then y has to be zero\r<BR>\n" );
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document.write( "Second problem<BR>\n" );
document.write( "X/(x+1)      (X-1)/(x+1)+2 = 1/2<BR>\n" );
document.write( "2x-2 =x+1+2   Solving for x = 4<BR>\n" );
document.write( "The original equations is x/x+1. = 4/4+1 = 4/5\r<BR>\n" );
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