document.write( "Question 1036195: Solve for n\r
\n" ); document.write( "\n" ); document.write( "log n + log(n+3)is equal to 2 \n" ); document.write( "

Algebra.Com's Answer #650848 by LinnW(1048) $\"\"$ $\"About$

You can put this solution on YOUR website!
log n + log(n+3) = 2
\n" ); document.write( "log(n(n+3)) = 2
\n" ); document.write( "If we are working with log base 10,
\n" ); document.write( "log(n(n+3)) = log(100), since log(100) = 2
\n" ); document.write( "So n(n+3) = 100
\n" ); document.write( "n^2 + 3n = 100
\n" ); document.write( "add -100 to each side
\n" ); document.write( "n^2 + 3n - 100 = 0
\n" ); document.write( "By quadratic formula
\n" ); document.write( "n = $\"+-%283%2F2%29+-+%28sqrt%28409%29%29%2F2+\"$
\n" ); document.write( "n = $\"+%28sqrt%28409%29%29%2F2+-%283%2F2%29++\"$ \n" ); document.write( "

\n" );