document.write( "Question 1036201: Find two numbers such that the first with half the second may make 55, and the second diminished by a fourth of the first may give 20.
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Algebra.Com's Answer #650832 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "the first with half the second may make 55.
\n" ); document.write( "x + y/2 = 55.......(1)
\n" ); document.write( "the second diminished by a fourth of the first may give 20.
\n" ); document.write( "y - x/4 = 20.......(2)
\n" ); document.write( "...........
\n" ); document.write( "x + y/2 = 55.......(1)
\n" ); document.write( "y - x/4 = 20.......(2)
\n" ); document.write( "Rearrange Eq(1)
\n" ); document.write( "y/2 + x = 55.......(1)
\n" ); document.write( "y - x/4 = 20.......(2)
\n" ); document.write( "Multiply Eq(2) by 4
\n" ); document.write( "y/2 + x = 55.......(1)
\n" ); document.write( "4y - x = 80.......(2)
\n" ); document.write( "Add Eq(1) + Eq(2)
\n" ); document.write( "4.5y = 135
\n" ); document.write( "y = 30
\n" ); document.write( "Substitute y = 30 into Eq(1).
\n" ); document.write( "x + y/2 = 55.......(1)
\n" ); document.write( "x + 30/2 = 55
\n" ); document.write( "x + 15 = 55
\n" ); document.write( "x = 55 - 15
\n" ); document.write( "x = 40
\n" ); document.write( "First number = 40
\n" ); document.write( "Second number = 30
\n" ); document.write( "Hope this helps :-)
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