document.write( "Question 1036169: What are the dimensions of a rectangle with an area of 81 sq. cm and a perimeter of 60 cm? \n" ); document.write( "
Algebra.Com's Answer #650794 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( " a rectangle with an area of 81 sq. \n" ); document.write( "Area of rectangle = length x width \n" ); document.write( "l x b = 81 \n" ); document.write( "l = 81/w \n" ); document.write( "Perimeter of rectangle = 2 x length + 2 x width \n" ); document.write( "60 = 2(81/w) + 2 x width \n" ); document.write( "60 = 162/w + 2w \n" ); document.write( "Multiply through by w \n" ); document.write( "60w = 162 + 2w^2 \n" ); document.write( "Sort into ax^2 + bx + c = 0 form \n" ); document.write( "2w^2 - 60w + 162 = 0 \n" ); document.write( "Divide by 2 \n" ); document.write( "w^2 - 30w + 81 = 0 \n" ); document.write( "Factorize \n" ); document.write( "(w - 3)(w - 27) = 0 \n" ); document.write( "w = 3 or 27 \n" ); document.write( "Using l = 81/w \n" ); document.write( "If w = 3cms then l = 27cms \n" ); document.write( "If w = 27cms then l = 3cms \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |