document.write( "Question 1036169: What are the dimensions of a rectangle with an area of 81 sq. cm and a perimeter of 60 cm? \n" ); document.write( "
Algebra.Com's Answer #650794 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( " a rectangle with an area of 81 sq.
\n" ); document.write( "Area of rectangle = length x width
\n" ); document.write( "l x b = 81
\n" ); document.write( "l = 81/w
\n" ); document.write( "Perimeter of rectangle = 2 x length + 2 x width
\n" ); document.write( "60 = 2(81/w) + 2 x width
\n" ); document.write( "60 = 162/w + 2w
\n" ); document.write( "Multiply through by w
\n" ); document.write( "60w = 162 + 2w^2
\n" ); document.write( "Sort into ax^2 + bx + c = 0 form
\n" ); document.write( "2w^2 - 60w + 162 = 0
\n" ); document.write( "Divide by 2
\n" ); document.write( "w^2 - 30w + 81 = 0
\n" ); document.write( "Factorize
\n" ); document.write( "(w - 3)(w - 27) = 0
\n" ); document.write( "w = 3 or 27
\n" ); document.write( "Using l = 81/w
\n" ); document.write( "If w = 3cms then l = 27cms
\n" ); document.write( "If w = 27cms then l = 3cms
\n" ); document.write( "Hope this helps :-)
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