document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89529>Question 89529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the system by addition<BR>\n" );
document.write( "2x - 9y = -4<BR>\n" );
document.write( "x - 4y = -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65077 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the second equation by -2 to get -2x+8y=2 ... add this result to the first equation to get\r<BR>\n" );
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document.write( "(2x-9y)+(-2x+8y)=-4+2 ... -y=-2 ... y=2 ... x-4(2)=-1 ... x=7 </SPAN>\n" );
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