document.write( "Question 1036125: \r
\n" ); document.write( "\n" ); document.write( "What number when multiplied by itself is 13 greater than the preceding number when it is multiplied by itself
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Algebra.Com's Answer #650732 by Aldorozos(172)\"\" \"About 
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x*x = 13 +(x-1)(x-1) = \r
\n" ); document.write( "\n" ); document.write( "x^2 = 13 + (x^2-2x - 1)
\n" ); document.write( "x^2 =13 + x^2 -2x +1
\n" ); document.write( "x^2 cancels out from both sides
\n" ); document.write( "We end of having -2x +14 = 0
\n" ); document.write( "Then x = 7 and the preceding number is 6
\n" ); document.write( "We know that if we multiply 7*7 = 13 + 6*6
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