document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036102>Question 1036102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At noon mr.Pryme decides to live kumasi for cape coast driving at 50km per hour.at 1:00pm Miss Anna live cape coast for kumasi driving at 60km per hour along the same route.If the two towns are 226km apart at what time will mr.Pryme meet Miss anna.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650715 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mr. Pryme leaves at noon, driving 50 kmh, giving him a 50 km headstart. Thus:<BR>\n" );
document.write( "50t+60t=226-50<BR>\n" );
document.write( "110t=176<BR>\n" );
document.write( "t=176/110 hours after 1:00 p.m.=96 minutes after 1:00 p.m.!!!!!!!!!!!!!!! </SPAN>\n" );
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