document.write( "Question 1036084: For questions 1-2 solve each equation on the interval [0,2pi). Show all work.\r
\n" ); document.write( "\n" ); document.write( "1. 4 sin^2 x + 2 sin x- 2 = 0\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. 2 sin(3x) = 1
\n" ); document.write( "

Algebra.Com's Answer #650698 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
4 sin^2 x + 2 sin x- 2 = 0
\n" ); document.write( "factor out a 2.
\n" ); document.write( "2(2sin^2 x+ sin x -1)=0
\n" ); document.write( "(2sinx-1)(sin x +1)=0
\n" ); document.write( "2 sin x -1=0, 2 sin x=1, sin x =(1/2), where it is at pi/6 and 5 pi/6.
\n" ); document.write( "sin x+1=0
\n" ); document.write( "sin x=-1
\n" ); document.write( "That is the case at 3pi/2.
\n" ); document.write( "====================
\n" ); document.write( "2sin (3x)=1
\n" ); document.write( "sin (3x)=(1/2)
\n" ); document.write( "The solutions above are divided by 3, so it occurs at 3x=pi/6, and pi/18 and 5pi/18 would be the solutions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );