document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035931>Question 1035931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the polar coordinates of the point with rectangular coordinates (1, -sqrt(3)). Use 0 <= theta <= 2pi and r >= 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650696 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We use these to convert to polar...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28x%5E2+%2B+y%5E2%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%28x%5E2+%2B+y%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ==> r = 2<BR>\n" );
document.write( "and<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta+=+tan%5E%28-1%29%28y%2Fx%29+=+tan%5E%28-1%29%28-1%2Fsqrt%283%29%29+=+5%2Api%2F6 ALIGN=MIDDLE  ALT=\"theta+=+tan%5E%28-1%29%28y%2Fx%29+=+tan%5E%28-1%29%28-1%2Fsqrt%283%29%29+=+5%2Api%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );