document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035983>Question 1035983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the accompanying diagram of right triangle ABC, AB = 5000 and angle C =90 degrees. If the measure of angle A is 20degrees40', find AC to the nearest unit.\r<BR>\n" );
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document.write( "Thanks for helping me out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650693 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw it you will see that the cosine of angle A is AC/AB, or<BR>\n" );
document.write( "cos A = AC/5000<BR>\n" );
document.write( "Now 40' of arc is 2/3 of a degree, or about .667, so we have<BR>\n" );
document.write( "cos 20.667 = AC/5000<BR>\n" );
document.write( "AC = 5000 cos 20.667 = 4678 or so units </SPAN>\n" );
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