document.write( "Question 1036076: Y varies directly as square root of Z and inversely as X cubed y equals 3 when Z equals 4 and x equals 2 find y if Z equals 16 and x equals 4 \n" ); document.write( "

Algebra.Com's Answer #650670 by fractalier(6550) $\"\"$ $\"About$

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The relationship looks like this:\r
\n" ); document.write( "\n" ); document.write( " $\"y+=+k%2Asqrt%28z%29%2Fx%5E3\"$
\n" ); document.write( "Now we plug in the original facts to find k...
\n" ); document.write( " $\"3+=+k%2Asqrt%284%29%2F2%5E3\"$
\n" ); document.write( "and we find
\n" ); document.write( "k = 12
\n" ); document.write( "Now we rewrite our relationship with the new k and plug in 2nd set of facts...
\n" ); document.write( " $\"y+=+12%2Asqrt%28z%29%2Fx%5E3+=+12%2Asqrt%2816%29%2F4%5E3+=+48%2F64+=+3%2F4\"$ \n" ); document.write( "

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