document.write( "Question 1036071: A collection of 18 coins, each of which is a nickel,dime or quarter, is worth $2.6. If there are 2 more quarters than nickels, how many of each are there? \n" ); document.write( "
Algebra.Com's Answer #650668 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
If we call their numbers n, d, and q, we can write
\n" ); document.write( "n + d + q = 18
\n" ); document.write( "and the value equation is
\n" ); document.write( "5n + 10d + 25q = 260 (we work in cents) and we also have
\n" ); document.write( "q = n + 2
\n" ); document.write( "let us substitute this third fact into the other two and get
\n" ); document.write( "n + d + n+2 = 18 and
\n" ); document.write( "5n + 10d + 25(n+2) = 260
\n" ); document.write( "which gives us
\n" ); document.write( "2n + d = 16 and
\n" ); document.write( "30n + 10d = 210
\n" ); document.write( "If we divide this second one by ten we can then subtract the first one from it...like this...
\n" ); document.write( "3n + d = 21
\n" ); document.write( "-(2n + d = 16)
\n" ); document.write( "---------------
\n" ); document.write( "n = 5 so that
\n" ); document.write( "q = 7 and then
\n" ); document.write( "d = 6
\n" ); document.write( "5 nickels = 25 cents
\n" ); document.write( "7 quarters = 175 cents
\n" ); document.write( "6 dimes = 60 cents
\n" ); document.write( "Total = 260 cents \n" ); document.write( "
\n" );