document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036073>Question 1036073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the measure of RQT is a straight angle what is the measure of angle RQS <BR>\n" );
document.write( "i'll try to draw it the best i can T__________Q/___________R i used the back slash mark to show which way ray QS is going in between TQ is the equation 6x+20 and in between RQS is the equation 2x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650662 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the measure of RQT is a straight angle what is the measure of angle RQS <BR>\n" );
document.write( "i'll try to draw it the best i can T__________Q/___________R i used the back slash mark to show which way ray QS is going in between TQ is the equation 6x+20 and in between RQS is the equation 2x+4 <BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "angle RQT = angle RQS + angle TQS<BR>\n" );
document.write( "180 degrees = 2x+4 + 6x+20<BR>\n" );
document.write( "8x + 24 = 180<BR>\n" );
document.write( "8x = 156<BR>\n" );
document.write( "x = 19.5<BR>\n" );
document.write( "----<BR>\n" );
document.write( "angle RQS = 2x+4 = 2*19.5+4 = 43 degrees<BR>\n" );
document.write( "angle TQS = 6x+20 = 6*19.5+20 = 137 degrees<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );