document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036053>Question 1036053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> mrs jones has a total of $2.11 in her drawer consisting of only pennies and dimes together she has 40 coins. find the number of pennies and dimes in her drawer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650659 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their numbers, p and d.  Then we can write<BR>\n" );
document.write( "p + d = 40 and the value equation is<BR>\n" );
document.write( "p + 10d = 211 (we work in cents)<BR>\n" );
document.write( "Now subtract equations and get<BR>\n" );
document.write( "p + d = 40<BR>\n" );
document.write( "-(p + 10d = 211)<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "-9d = -171<BR>\n" );
document.write( "d = 19 dimes and that means she has<BR>\n" );
document.write( "p = 21 pennies </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );