document.write( "Question 1036042: What number when multiplied by itself is 13 greater than the preceding number when it is multiplied by itself \n" ); document.write( "
Algebra.Com's Answer #650633 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
What kind of preceding number?\r
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\n" ); document.write( "\n" ); document.write( "The number to multiplied by itself, x.
\n" ); document.write( "Some unspecified preceding number, n.
\n" ); document.write( "\"x%2Ax=13%2Bn%2An\"
\n" ); document.write( "\"x%5E2=n%5E2%2B13\"
\n" ); document.write( "\"x=sqrt%28n%5E2%2B13%29\", but this should be \"x=0%2B-+sqrt%28n%5E2%2B13%29\".\r
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\n" ); document.write( "\n" ); document.write( "If your preceding number should be an integer, then you may want \"n=x-1\". This will give the initial equation as \"x%5E2=%28x-1%29%5E2%2B13\" and then you could solve this for x.\r
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\n" ); document.write( "You could accept the assumption I described, and you should be able to solve the resulting \"x%5E2=%28x-1%29%5E2%2B13\" without trouble.
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