document.write( "Question 1035971: if a, b, c, d are in continued proportion, prove that a^3 + b^3 + c^3 : b^3 + c^3 + d^3 = a : d. \n" ); document.write( "
Algebra.Com's Answer #650630 by robertb(5830)\"\" \"About 
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a, b, c, d in continued proportion ==> a/b = b/c = c/d = k for some constant of proportionality k \r
\n" ); document.write( "\n" ); document.write( "==> \"a+=+bk+=+ck%5E2+=+dk%5E3\"\r
\n" ); document.write( "\n" ); document.write( "==> \"b+=+a%281%2Fk%29\", \"c+=+a%281%2Fk%29%5E2\", and \"d+=+a%281%2Fk%29%5E3\", and so a,b,c, and d form a geometric sequence.\r
\n" ); document.write( "\n" ); document.write( "==>.\r
\n" ); document.write( "\n" ); document.write( "BUT, \"a+=+dk%5E3\", and so \"k%5E3+=+a%2Fd\", and the statement is proved.
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