document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89511>Question 89511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just need help setting up the equation. It's from Algebra, Part 3 from Thomson Education Direct. It's a career oriented study unit. # of book is 2469C-1\r<BR>\n" );
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document.write( "A person travels 4 hrs by plane and 25 hrs by ship and covers a total distance of 1580 miles. If the plane's speed would have been 1/2 of the actual speed and the ship's speed 1/4 greater than the actual speed, a distance of 1315 miles would have been travelled. Find the speeds of the plane and the ship. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65063 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rate*time=distance ... p equals plane speed, s equals ship speed ... 4p+25s=1580 ... 4(p/2)+25(s(5/4))=1315\r<BR>\n" );
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document.write( "here are the equations ... let me know if you need help with the solution </SPAN>\n" );
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