document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1035997>Question 1035997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please help me I don't understand it if the measure of angle RQT is a straight angle what is the measure of angle RQS i\"ll try to draw as much as I can, T________Q________R it then shows a ray going from going up at an angle it then shows the equation 6x+20 sitting on TQ it then shows the equation 2x+14 sitting between RQS someone wrote me the answer of 88 degrees but the acellus site says it's wrong </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650619 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if i understand this correctly, your two angles are:\r<BR>\n" );
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document.write( "angle TQS = 6x + 20<BR>\n" );
document.write( "angle SQR = 2x + 14\r<BR>\n" );
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document.write( "these angles are supplementary, therefore the sum of their measures is 180 degrees.\r<BR>\n" );
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document.write( "you get 6x + 20 + 2x + 14 = 180<BR>\n" );
document.write( "combine like terms to get 8x + 34 = 180<BR>\n" );
document.write( "subtract 34 from both sides of this equation to get 8x = 146<BR>\n" );
document.write( "divide both sides of this equation by 8 to get x = 18.25\r<BR>\n" );
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document.write( "x = 18.25<BR>\n" );
document.write( "6x + 20 = 129.5<BR>\n" );
document.write( "2x + 14 = 50.5<BR>\n" );
document.write( "the sum of the angles is 129.5 +50.5 = 180\r<BR>\n" );
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document.write( "the solution looks good.\r<BR>\n" );
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document.write( "angle TQS is equal to 129.5 degrees.<BR>\n" );
document.write( "angle SQR is equal to 50.5 degrees. </SPAN>\n" );
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