document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1036017>Question 1036017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express (3cis 60°)(2cis 75°) in polar form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #650615 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=650615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283cis+60%5Eo%29%282cis+75%5Eo%29+=+3cis135%5Eo+=+3%28cos135%5Eo+%2B+isin135%5Eo%29 ALIGN=MIDDLE  ALT=\"%283cis+60%5Eo%29%282cis+75%5Eo%29+=+3cis135%5Eo+=+3%28cos135%5Eo+%2B+isin135%5Eo%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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