document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89502>Question 89502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with these problems please explain them to me step by step thanks....I have an exam tomorrow i want to really understand them;.....\r<BR>\n" );
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document.write( "Problem #1<BR>\n" );
document.write( "Find the percent of the total area under a normal curve that is contained within the specified interval. Between the mean and 1.64 standard deviations from the mean\r<BR>\n" );
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document.write( "Problem #2<BR>\n" );
document.write( "Find the percent of the total area under the standard normal curve between the given z-scores.\r<BR>\n" );
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document.write( "z= -1.10 and z = -0.36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65060 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem #1<BR>\n" );
document.write( "Find the percent of the total area under a normal curve that is contained within the specified interval. Between the mean and 1.64 standard deviations from the <BR>\n" );
document.write( "You need a z-chart or a calculator with z capability, like a TI 83 or 84<BR>\n" );
document.write( "On the z cart find z=1.64.  The chart tells you the area over the interval<BR>\n" );
document.write( "[0,1.64] = 0.9495-0.5000 = 0.4495<BR>\n" );
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document.write( "Problem #2<BR>\n" );
document.write( "Find the percent of the total area under the standard normal curve between the given z-scores. <BR>\n" );
document.write( "z= -1.10 and z = -0.36<BR>\n" );
document.write( "Look up z = 1.10 = 0.8643-0.5000 = 0.3643<BR>\n" );
document.write( "Look up z = 0.36 = 0.6406-0.5000 = 0.1406<BR>\n" );
document.write( "Subtract the 2nd area from the 1st to get 0.2237<BR>\n" );
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document.write( "Comment: Your z-chart might be arranged differently<BR>\n" );
document.write( "but the final figure you get should be the same <BR>\n" );
document.write( "as the one I have.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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